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C51单片机脉冲累加器(C语言程序)

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1级

2016-10-21 回答

#include

#define uchar unsigned char

#define uint unsigned int

sbit key =P2^5;

sbit key1=P2^4;

sbit key2=P2^3;

sbit key3=P2^2;

sbit pwm=P1^0;

uint pwm_value=1960;

uint count=0;

void timer0(void) interrupt 1 using 1

{

switch(count)

{

case 1:pwm=1;

TH0=-pwm_value/256;

TL0=-pwm_value%6;

break;

case 2: pwm=0;

TH0=-(2700-pwm_value)/256;

TL0=-(2700-pwm_value)%6;

break;

/*case 3:pwm1=1;

TH0=-pwm_value/256;

TL0=-pwm_value%6;

break;

case 4: pwm1=0;

TH0=-(2700-pwm_value)/256;

TL0=-(2700-pwm_value)%6;

break;

case 5:pwm2=1;

TH0=-pwm_value/256;

TL0=-pwm_value%6;

break;

case 6: pwm2=0;

TH0=-(2700-pwm_value)/256;

TL0=-(2700-pwm_value)%6;

break;

case 7:pwm3=1;

TH0=-pwm_value/256;

TL0=-pwm_value%6;

break;

case 8: pwm3=0;

TH0=-(2700-pwm_value)/256;

TL0=-(2700-pwm_value)%6;

break;

case 9:pwm4=1;

TH0=-pwm_value/256;

TL0=-pwm_value%6;

break;

case 10: pwm4=0;

TH0=-(2700-pwm_value)/256;

TL0=-(2700-pwm_value)%6;

break;

case 11:pwm5=1;

TH0=-pwm_value/256;

TL0=-pwm_value%6;

break;

case 12: pwm5=0;

TH0=-(2700-pwm_value)/256;

TL0=-(2700-pwm_value)%6;

break;*/

default: count=0;

}

count ;

}

void InitTimer0(void)

{

count=1;

TMOD=0x11;

TH0=-1500/256;

TL0=-1500%6;

EA=1;

ET0=1;

TR0=1;

}

void delay(void)

{

uint i=100;

while(i--);

}

void main(void)

{

InitTimer0();

while(1)

{

if(pwm_value<2200)

pwm_value =2;

if(pwm_value>1000)

pwm_value-=2;

}

}

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