;对这个题目进一步改造: ;3_7 用户输入一个由数字‘0’~‘9’英文大写字母‘A’~‘Z’;以及英文小写字母‘a’~‘z’组成的ASCII 字符串， ;字符串的结束符为 CR（即回车符，其ASCII 码为0DH），字符串总长度不超过256 个。 ;要求统计传送的字符总数以及其中各种字符的数目 
DATA SEGME SUM 00H ;总数 CTAL DB 00h ;大写字母个数 计数器 small db 00h ;小写字母个数 计数器 num db 00h ;数字个数 计数器 result db 'The amout all of the zifu in this string is ','$' result1 db 'The amout of the number in the string is ','$' result2 db 'The amout of the big capital is ','$' result3 db 'The amout of the small capital is ','$' string db 256 dup (?) ;保存输入的字符 kongzi DB 0DH,0AH,'$' ;换行使用 buffer DB 256 DUP(0) ;目标内存 results DB 256 DUP(?) tital db 'Please input the string you want to be done : ',0dh,0ah,'$' tip db 'Do you want to have a try again (if yes: "y" ,else "n"): ','$' tip1 db 'welcome to use the program again ,the original is WQ ','$' DATA ENDS CODE SEGMENT ASSUME CS:CODE,DS:DATA ART: MOV AX,DATA MOV DS,AX lea dx,tital mov ah,09h int 21h mov di,0 again: mov ah,01h int 21h mov string[di],al inc di cmp al,0dh jnz again cld ;将方向标志位置零 串操作递增 main: lods string ;字符串装入指令 把字符串一个个装入al INC SUM CMP AL,0DH JE DE CMP AL,30H Jb main cmp al,41h jb k1 CMP AL,61H Jb k2 JMP main DONE: lea dx,result ;输出SUM mov ah,09h int 21h DEC SUM MOV AX,0 MOV AL,SUM MOV BL,10 DIV BL MOV DX,AX ADD DX,3020H ;为什么要加20呢？ cmp dl,30h jnz wuling mov dl,20h wuling: MOV AH,02h INT 21H MOV DL,DH ;这是在干什么？ MOV AH,2h ;2号调用每次只输出一个字符，即dl INT 21H LEA DX,kongzi ;换行 MOV AH,09H INT 21H ;输出num mov ax,0 mov al,num mov bl,10 div bl mov dx,ax add dx,3030h cmp dl,30h jne wuling3 mov dl,32 wuling3: push dx lea dx,result1 mov ah,09h int 21h pop dx mov ah,02h int 21h mov dl,dh mov ah,02h int 21h LEA DX,kongzi MOV AH,09H INT 21H ;输出CAPITAL MOV AX,0 MOV AL,CAPITAL sub al,04h MOV BL,10 DIV BL MOV DX,AX ADD DX,3030H CMP Dl,30H JNE WULING2 MOV Dl,32 WULING2:push dx lea dx,result2 mov ah,09h int 21h pop dx MOV AH,02h INT 21H MOV DL,DH MOV AH,2 INT 21H mov al,sum sub al,capital add al,04h sub al,num mov small,al ;输出small capital MOV AX,0 MOV AL,small MOV BL,10 DIV BL MOV DX,AX ADD DX,3020H CMP Dl,30H JNE WULING4 MOV Dl,32 ;空格 WULING4: push dx LEA DX,kongzi MOV AH,09H INT 21H lea dx,result3 mov ah,09h int 21h pop dx MOV AH,02h INT 21H MOV DL,DH MOV AH,2 INT 21H lea dx,kongzi mov ah,09h int 21h lea dx,tip mov ah,09h int 21h mov ah,01h int 21h cmp al,'y' je lop lea dx,kongzi mov ah,09h int 21h lea dx,tip1 mov ah,09h int 21h over: MOV AH,4CH INT 21H k2:inc capital jmp main k1: inc num jmp main lop: lea dx,kongzi mov ah,09h int 21h jmp start CODE ENDS END START